Rakesh solved some problems of exponents in the following way. Do you agree with the solutions? If not why ? Justify your argument.(i) x⁻³ × x⁻² = x⁻⁶(ii) x³/x² = x⁴(iii) x⁻² = √xiv) 3x⁻¹ = 1/3x
Answers
Answered by
19
No, All solutions are wrong.
Justification:
(i)
when Bases are equal powers should be added.
-3 + (-2) = -3-2 = -5
so x^-5 is the right one
(ii)
When there exists equal bases in numerator and denominator, but with both having different powers, subtract power of denominator from numerator.
3 - 2 = 1
so x is the right answer
(iii)
When a power is negative, it indicates inverse or reciprocal.
so 1/x² is right one.
(iv)
same as 3rd, -ve power
3/x is the correct answer
Hope it helps
^_^
If you find this helpful mark it as brainliest..
Justification:
(i)
when Bases are equal powers should be added.
-3 + (-2) = -3-2 = -5
so x^-5 is the right one
(ii)
When there exists equal bases in numerator and denominator, but with both having different powers, subtract power of denominator from numerator.
3 - 2 = 1
so x is the right answer
(iii)
When a power is negative, it indicates inverse or reciprocal.
so 1/x² is right one.
(iv)
same as 3rd, -ve power
3/x is the correct answer
Hope it helps
^_^
If you find this helpful mark it as brainliest..
Answered by
10
Please mark as brainliest answer
Attachments:
Similar questions