Ram and Mehmood are two neighboures. Ram wears a cap which is in the shape
of hemisphere of radius 7 cm. and Mehmood wears a turkish cap which is in the
shape of frustum of a cone. If radius of its open side is 10 cm and radius of the
upper base is 4 cm and its slant height is 15 cm. Find the curved surface area of
both caps.
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Step-by-step explanation:
CSA of Ram's cap
2πr^2= 2× 22÷7×7×7
= 308 cm^2
CSA of mehmood's cap
πl (R +r) = 22 ÷7 ×15 (10+4)
= 22× 15×14÷7
=660 cm ^2
Total CSA of both the caps
308 +660 = 968 cm ^2
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