Question

Ram and Sham are running in opposite direction around a circular track

of length 20π meters. Speed of Ram is 33.33% of the speed of Sham. Find

straight line distance between their first meeting point and the second

meeting point. It is given that they start simultaneously from a common

starting point.​

Answer 1

Answer:

10 × squareroot(2) meters = 14.142 meters is the answer.

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Explanation:

Since Ram is at 1/3rd speed slower than Sham.

Hence, Ram:Sham speeds= 1:3.

Ram: their total speeds= 1:4.

This means that when Ram runs 1/4th (25%) of the circumefrence, then Sham run the remaining 3/4th (75% = 25% ×3) of the circumerence.

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Hence, their first meeting point was at point, when Ram ran 1/4th of the circumference.

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Similarly, their second meeting point was at point, when Ram ran additional 1/4th of the circumference (i.e. total 1/2).

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This makes 90 degrees of angle (i.e. 360/4 degrees), between the two consecutive meeting point.

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Now, our work is very simple.

If we measure the distenace by the circular track, then total distance between 2 meeting points would be:

total circumference/4 = 20×pi /4 = 5×pi.

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But, we have been asked to calculate the distance in a straight line. Since, 90 degrees means we can use the Pythagorus theorem to find out simply the required answer.

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answer = squareroot(radius^2 + radius^2).

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So, lets calculate the radius.

circumference= 20× pi= 2× pi ×radius

Thus, radius= 10 meters.

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Hence, answer = squareroot(10^2 + 10^2) = 10×squareroot(2) = 14.142 m.