Ram and Shyam are 10 km apart. They both see a hot air balloon passing in the sky making an angle of 60° and 30° respectively. What is the height at which the balloon could be flying?☺✌
Answers
Answer:
According to question,
Ram and Shyam are 10km away from each other.
Let say that hot air balloon is height h above the ground where Ram and Shyam are standing and also lets assume that the ballon is directly above from that point on ground which is x km away from Ram and so (10-x) km away from Shyam.
Now using Trigonometry,
Also, 60° is the angle which it made on Ram side and 30° is the angle which it made on Shyam side.
Therefore, tan60° = x/h and tan30° = (10-x)/h
So we can also write it as,
h = x/tan60° (1)
h = (10-x)/tan30° (2)
Equating (1) and (2):
x/tan60° = (10-x)/tan30°
You know that tan60° = √3 and tan30° = 1/√3, applying them in above equation, we will get:
x/√3 = (10-x)/(1/√3)
-> x/√3 = √3*(10-x)
Multiply √3 on both sides,
(x*√3)/√3 = √3*√3*(10-x)
x = 3*(10-x)
x = 30 - 3*x
Adding 3*x on both sides,
x + 3*x = 3*x +30 - 3*x
4*x = 30
Dividing 4 on both sides,
4*x/4 = 30/4
x = 7.5 km
This implies the point directly above which balloon is there is 7.5km away from Ram and 2.5km away from Shyam( Combining 7.5 + 2.5 = 10km).
Put value of x in either equation (1) or (2) to get the value of h (I'm putting it in (2), you can even put it in (1), the result will remain same in both cases)
h = (10 - 7.5)/(1/√3)
h = 2.5/(1/√3)
h = √3*2.5
So the height at which ballon is there is √3*(5/2) km or
4.33km (above the ground).
I hope you have understood the answer
Step-by-step explanation:
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Step-by-step explanation:
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