Ram and Shyam are pushing two identical boxes. Ram is pushing box I that is placed on a wheel cart, while
Shyam is pushing box II that is placed on the ground. Both Ram and Shyam are trying to maintain a steady motion
of the boxes. It is relatively difficult for Shyam to maintain a steady motion of box II because
Answers
Answer:
because rolling friction is less than kinetic friction
please mark me as the brainliest and thank my answers and follow me
Answer:
Since both the boxes rest on the same floor, the coefficient of static friction is nothing to worry about. What you have to worry about is the normal force because limiting friction is coefficient of static friction times the normal force. Also, the boxes are of the same size implying the volume of both is the same. However, they have not specified anything about density. So, it is logical to assume one of the boxes to have a greater density. Since density is mass over volume, the box with a greater density will have more mass. The gravitational force acting on the heavier box is greater than that acting on the lighter one. Knowing that the box is in vertical equilibrium, it is evident that the normal force is equal to the gravitational force. So, the heavier box will experience greater normal force. This tells us that the heavier box will have a higher value of limiting friction. It is therefore difficult to push the heavier one. You would have to exert a greater force to give rise to an acceleration equal to that of the lighter box. So Ram was pushing the denser box or in this context, the heavier box.
hope this helps,mark the answer as brainliest and follow me
THANKS^_^
___SAMIKSHA2714___