Math, asked by haripriyakumar001, 8 months ago

ram and shyam start walking at 12 noon from points A and B respectively towards B and A at constant but different speeds, they met at 4 pm. If ram takes 6 hours more to reach point B than the time taken by shyam to reach point A what time does shyam takes to reach point A?​

Answers

Answered by amitnrw
5

Given : ram and shyam start walking at 12 noon from points A and B respectively towards B and A at constant but different speeds, they met at 4 pm. If ram takes 6 hours more to reach point B than the time taken by shyam to reach point A

To find : what time does shyam takes to reach point A

Solution:

Speed of Ram  =  R km/hr

Speed of Shyam = S km/hr

They meet each other after 4 hrs

=> Total Distance = 4R + 4S  km

Let say shayam take further T  Hrs

Then Ram takes further = T + 6 hrs

ST  =  4R     ( distance to be covered by shayam = Distance already covered by Ram )

R(T + 6)  = 4S    ( distance to be covered by Ram = Distance already covered by Shayam )

ST  =  4R

4S  = R(T + 6)

Dividing both

=> T/4  = 4/(T + 6)

=> T² + 6T = 16

=> T² + 6T - 16 = 0

=>  (T + 8)(T - 2) = 0

=> T = 2

4 + 2 = 6

Shayam reached point A  at 6 PM  

He takes 6 hrs

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