Math, asked by aishwaryamaniyar, 9 months ago

Ram and Shyam were playing. Ram asks Shyam to form numbers with the digits 4,3, 8 and 1. He gives him three different cases as i. Form the largest four digit number with no repetition of digits. ii. Form the largest four digit where two digits can be repeated twice. iii. Form the smallest four digit number where repetition of digits is allowed four times. What are the numbers?

Answers

Answered by creativevishnu4
0

Answer:

i. 8431

ii. 8844

iii. 1111

I wrote these numbers by following the rules mentioned in the question.

Please mark as brainliest if it is helpful.

Answered by smithasijotsl
0

Answer:

(1) 8431

(2) 8844

(3) 1111

Step-by-step explanation:

Given digits are 4,3,8,1

(i)Form the largest four-digit number with no repetition of digits.

To get the largest number, without repeating digits, we should write the digits in the descending order.

Without repeating the digits the largest four-digit number can be formed = 8431

(ii) Form the largest four-digit where two digits can be repeated twice.

To get the largest four-digit number, where two digits are repeating we should choose the largest of the two digits and write it with descending order

The largest four-digit number with two digits repeating twice =8844

(iii)Form the smallest four-digit number where repetition of digits is allowed four times.

To ger the smallest four-digit number with repetition of digits 4 times, is obtained by repeating the smallest digit four times

Hence the four-digit number with repeating digits 4 times =1111

#SPJ3

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