Question

Ram and Shyam were walking in the park one evening. Shyam had a test that morning and was
fascinated by a sum asked by the teacher. He wanted to test whether Ram was able to do that sum.
Shyam asked the same sum to Ram.
The sum of the digits of a
the resulting new number will be greater than the original number by 27.
19. If the digit in the one’s place of the two
a) 9 + x b) 9
20. The original two-digit number is:
a) 90x – 11x b) 90
21. The new number formed by interchanging the digits will be
a) 9x+9
22. The original number is
a) 63 b) 36

Answer 1

Answer:

Solution

Let digit at unit's place be x and ten's place by y.

∴ Number = 10y + x

On reversing the digits, the new number = 10x + y

According to given condition,

x + y = 9 …(1)

and 10x + y = 27 + (10y + x)

implies 9x - 9y = 27

implies x - y = 3 ...(2)

Adding equations (1) and (2), we get

2x = 12

implies x = 6

Putting x = 6 in equation (1), we get

6 + y = 9 implies y = 3

Hence, the required number = 10y + x = 10 × 3 + 6 = 36

Step-by-step explanation:

. The new number formed by interchanging the digits will be

a) 9x+9

Answer 2

Given :  The sum of the digits of a two digit number is 9.

When we interchange the digits, it is found that the resulting new number will be greater than the original number by 27.

https://brainly.in/question/48299518  (correct Question )

digit in the one’s place of the two-digit number is ‘x’

To Find : The digit in the ten’s place will be

The original two-digit number is

The new number formed by interchanging the digits will be

original number is

Solution:

Digit at one's place  = x

Sum of Digits  = 9

Hence Digits at Ten's place = 9 - x

Tens Digit = 9 - x

one's Digit = x

Original Number = 10 (9 - x) +x   = 90 - 9x

Number formed by interchanging digits

= 10x + (9 - x)

= 9x  + 9

9x + 9  = (90 - 9x ) + 27

=> 18x  = 108

=> x = 6

Original Number  = 90 - 9(6) = 36

Original number is 36

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