Question

Ram appeared in 3 tests of 20, 30 & 50 marks respectively. He obtained 75% marks in the 1st & 60% in

2nd test. What should be his percentage of marks in 3rd test so that his aggregate is 60%?

(Hint:-Answer is 54%) shows steps​

Answer 1

Step-by-step explanation:

= 60÷4=15

= 15 ×3=45

= 45 + 8= 54

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Answer 2

Answer:

His percentage of marks in third exam should be 54%.

Step-by-step explanation:

Given,Ram appeared in 3 tests and full marks of first exam is 20,full marks of second exam is 30 and full marks of third exam be 50.

Now,he get 75% in first exam.

Therefore he get in first exam

$= 75\% \: of \: 20 \\ = \frac{75}{100} \times 20 \\ = \frac{3}{4} \times 20 \\ = 3 \times 5 \\ = 15$

Again he get 60% in second exam.

Therefore he get in second exam

$= 60\% \: of \: 30 \\ = \frac{60}{100} \times 30 \\ = 6 \times 3 \\ = 18$

It is also given his aggregate in three exam total 60%.

Total marks of three exams

$= 20 + 30 + 50 \\ = 100$

So,he get total in three exams

$= 60\% \: of \: 100 \\ = \frac{60}{100} \times 100 \\ = 60$

Here we want to find percentage his marks of third exam.

Let he get x% in third exam.

So he get in third exam

$= x\% \: of \: 50 \\ = \frac{x}{100} \times 50 \\ = \frac{x}{2}$

According to question,

$15 + 18 + \frac{x}{2} = 60 \\ 33 + \frac{x}{2} = 60 \\ \frac{x}{2} = 60 - 33 \\ \frac{x}{2} = 27 \\ x = 27 \times 2 \\ x = 54$

Therefore he get 54% in his third exam.

This is a problem of percentage.

Know more about percentage.

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