Math, asked by lknayak2005, 1 day ago

Ram borrowed a sum of ₹ 30000 from shyam for 3 years. If the rate of interest is 6%per annum compounded annually, find the interest paid by ram to shyam after 3 years ​

Answers

Answered by Anonymous
32

Given :

  • Principal = ₹ 30000
  • Rate = 6 %
  • Time = 3 years

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To Find :

  • Compound Interest = ?

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Solution :

~ We know that :

  • Amount :

 {\color{orange}{\bigstar}} \: \: {\underline{\boxed{\color{darkblue}{\sf{Amount = Principal \bigg\{ 1 + \dfrac{Rate}{100} \bigg\}^{Time} }}}}}

  • Compound Interest :

 {\color{orange}{\bigstar}} \: \: {\underline{\boxed{\color{darkblue}{\sf{Compound \; Interest = Amount - Principal }}}}}

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~ Calculating the Amount :

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = Principal \bigg\{ 1 + \dfrac{Rate}{100} \bigg\}^{Time} }}}} \\

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = 30000 \bigg\{ 1 + \dfrac{6}{100} \bigg\}^3 }}}} \\

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = 30000 \bigg\{ 1 + \cancel\dfrac{6}{100} \bigg\}^3 }}}} \\

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = 30000 \bigg\{ 1 + 0.06 \bigg\}^3 }}}} \\

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = 30000 \bigg\{ 1.06 \bigg\}^3 }}}} \\

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = 30000 \times 1.06 \times 1.06 \times 1.06  }}}} \\

 \: \: {\dashrightarrow{\qquad{\sf{ Amount = 30000 \times 1.191016 }}}} \\

 \qquad \: {\green{:\implies{\underline{\boxed{\red{\sf{Amount =  ₹ \: 35730.48 }}}}}}}

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~ Calculating the Interest :

 \\

 \: \: {\longrightarrow{\qquad{\sf{ Compound \; Interest = Amount - Principal }}}} \\

 \: \: {\longrightarrow{\qquad{\sf{ Compound \; Interest = 35730.48 - 30000 }}}} \\

 \qquad \: {\pink{:\implies{\underline{\boxed{\orange{\sf{Compound \: Interest =  ₹ \: 5730.48 }}}}}}}

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~ Therefore :

❝ The compound Interest is ₹ 5730.48 . ❞

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Answered by Anonymous
36

Given

  • Ram borrowed a sum of ₹ 30000 from shyam for 3 years. If the rate of interest is 6%per annum compounded annually, find the interest paid by ram to shyam after 3 years

 {\qquad {\rule{999pt}{0.9pt}}}

To Find

  • Interest?

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Solution

Formula Used

  \pink\bigstar \boxed{ \sf{A=P(1+r) t}}

  \red\bigstar \boxed{ \sf{ Compound  \: interest \:  = Amount - Principal}}

Putting Values According To Formula

{ \longmapsto{ \sf{A=30000(1+0.06)^3}}}

{ \longmapsto{ \sf{A=30000(1.06)^3}}}

{ \longmapsto{ \sf{A=30000(1.191016)}}}

{ \longmapsto{ \sf{A=35730.48}}}

So, The amount is Rs.35730.48.

 \qquad \rule{999pt}{0.88pt}

The compound interest is amount - principal.

Compound interest = Amount - Principal

{ \sf{Compound  \: interest =  \bf \red{ 35730.48 - 30000}}}

{ \sf{Compound  \: interest =  \bf \red{ 5730.48 }}}

Therefore,

“The interest paid by Ram to Shyam after 3 years is Rs.5730.48.”

 {\underline {\rule{999pt}{9pt}}}

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