Ram borrows Rs.22500 at 10percent per annum, compounded annually. If he repays Rs. 11250 at the end of first year and Rs12550at the end of the second year, find the amount of loan outstanding against him at the end of third year.
Answers
Answer:
Suppose a triangle ABC, right-angled at C.
Now, we know the trigonometric ratios,
cos A = AC/AB
cos B = BC/AB
Since, it is given,
cos A = cos B
AC/AB = BC/AB
AC = BC
We know that by isosceles triangle theorem, the angles opposite to the equal sides are equal.
Therefore, ∠A = ∠B
Answer:
▪︎Given that
Given thatPrincipal (P) = Rs.22500
Given thatPrincipal (P) = Rs.22500Rate (r) =10% p.a.
Given thatPrincipal (P) = Rs.22500Rs.
▪︎We need to find theamount of loan outstanding against him at the end of the third yearLet us calculate the amount yearlyBeginning with the first year:
Amount paid at the end of first-year =Rs. 11250 (given)
Amount paid at the end of first-year =Rs. 11250 (given)Balance = Rs.24750 – Rs.11250 =Rs.13500
Amount at the end of 2nd year = Rs.13500 (1+10/100)1 = Rs.13500 x 11/10 = Rs.14850
Amount paid at the end of 2nd-year =Rs.12550 (given)
Amount at the end of 3rd year = 2300 (1+10/100)1 = 2300 x 11/10 = Rs.2530
{Amount paid at the end of 3rd year = Rs. 2530}
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