Question

ram drives a scooter wiyh velocity 36km/h and after 5 sec he increased his velocuty by double find the acceleration and covered distance​

Answer 1

Answer:

v=36 km/hr

v=36×

18

5

=10 m/s

u=0

t=10 sec

v=u+at

10=0+a(10)

10=10a

a=1 m/s

2

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Answer 2

acceleration =2 m/s^2,distance =75 metres

Explanation:

initial velocity of ram=36km/h

36×5÷18=10 m/s^2

after 5 seconds= velocity doubles thus final velocity becomes 20m/s^2

so acceleration =final velocity- initial velocity/time

thus 20- 10/5=2m/s^2

we know that 2as=v^2- u^2

therefore by putting values

a=2m/s^2,v=20m/s,u=10m/s

we get s=75 metres