Ram goes a to
b.If he takes 1/4 time less than to cover the same distance when run at normal speed by what % he has incresed the speed ?
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let distance =x
and time=t
s=x/t
when he run at speed
t'=t-1/4t
t'=3/4t
distance remain same
s*t=s'*3/4t
s'=4/3s
%increase in speed=33.3%
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