ram got 8 marks more than shyam in an examinations anil got 4marks more than ram in the same examinations if all three of them got 128 marks together as a total ram marks would be
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Answered by
5
let,
anil's mark be x
shyam's mark be y.
so, ram mark = 8 + y
ram mark = 4 + x
so, 8+y = 4+x
x-y = 4
now, x+y+6+x = 128
2x+y = 122
now solve the above
x - y = 4
2x + y = 122
then x = 43
therefore, ram's mark = 43 + 4 = 47 marks
anil's mark be x
shyam's mark be y.
so, ram mark = 8 + y
ram mark = 4 + x
so, 8+y = 4+x
x-y = 4
now, x+y+6+x = 128
2x+y = 122
now solve the above
x - y = 4
2x + y = 122
then x = 43
therefore, ram's mark = 43 + 4 = 47 marks
hdewangan:
It is wrong
Answered by
11
Let marks of shyam be x
Then marks of ram = x+8
Marks of anil = x+12
Total marks = 128
x+x+8+x+12= 128
3x +20 = 128
3x = 128-20
3x = 108
x = 108/3
x = 36 = Marks of shyam.
Marks of Ram = x+8
= 36+8
= 44
Marks of Anil = x+12
= 36+12
=48
If you satisfied mark it brainliest.
Then marks of ram = x+8
Marks of anil = x+12
Total marks = 128
x+x+8+x+12= 128
3x +20 = 128
3x = 128-20
3x = 108
x = 108/3
x = 36 = Marks of shyam.
Marks of Ram = x+8
= 36+8
= 44
Marks of Anil = x+12
= 36+12
=48
If you satisfied mark it brainliest.
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