Question

Ram has 18 coins in the denomination of Re 1, Re 2 and Re 5 . if their total value is Rs 54 and the number of Re 2 are greater than that of Re 5 coins, then find the number of Rupees 1 coins with him​

Answer 1

Answer:

Dj dj djd jd js jd nsbsjkYGskUshsmisfsmdisfzmzisgdmodhdldidjdoz

Step-by-step explanation:

naksjsbzljz sozgzmzyzgsksgsbsysvsfsjfdshsysfsvysgsgsisisfbsjsgsgsjsoshsmsufsmsosgsbsjsysfkTsvsursjyzvsnzbznzbbzjzvskhsbdhsvhsvshsbsydbhsgsgshsgdgdhdhshsgsgdgsgdgdyisgshdudgdhsosyfskacvdhss

Answer 2

Answer:

3

Step-by-step explanation:

Let the total no. of 1 Re coins be x, 2Re coins be y and 3Re coins be z

So,

1x + 2y + 3z =54 , where y>z

Then,

x +2y +5z =54

(18-y-z)+ 2y +5z =54

y +4z =36

As y is greater than z putting all the favorable values of z we conclude that z=7 and y=8

Hence,

x+y+z =18

x=18-8-7

x=3