Question

Ram has rs. 6 more than mohan and rs. 9 more than sohan. all the three have rs. 33 in all. ram has a share of

Answer 1

Ram has Rs. x
Mohan has Rs. y
Sohan has Rs. z




$x = y + 6$
$x = z + 9$

$x + y + z = 33$
$x - y = 6$
$2x + z = 39$
$x - z = 9$
solving we get

$3x = 42$
$x = 14$
$y = 8$
$z = 11$

Answer 2

Lets ram's money be x
Then mohan's money will be = (x - 6)
Sohan's money will be = (x - 9)
Then
  x + (x - 6) + (x - 9) = 33
  x + x - 6 + x - 9 = 33
  x + x + x - 6 - 9 = 33
  3 x - 15 = 33
  3 x = 33 + 15
  3 x = 48
  x = 48 /3
  x = 16 
So Ram has a share of 16 rupees