Ram is driving a car with a speed of 36 km/hr.
When he was 275 m distant from the railway
crossing suddenly he saw the timer is showing 15
seconds remaining in closing and he accelerates
his car with 2 m/s?, after 10 seconds he realized,
it is risky so he applied brakes. What should be
the minimum deceleration of the car so that the
car stopped just before the crossing?
[3]
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Answer:
distance covered by car in 10s with accelareion 2m/s2=36×518×10+12×2×(10)2=200mremaining distance=275−200=75and velocity of car after 10s=36×518+2×10=30m/sand let decelaration of the car is b thenby third equation of motion 0=302+2b×75b=−900150=−6m/s2
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(・∀・) it's in the pic
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