Ram is travelling with 20m/s and stopped in 4 sec. What is his acceleration in m/s^2?
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Explanation:
Initial velocity of car, u = 20 m/s
The final velocity will be, v= 0 as the car comes to rest after travelling distance of 40 m (which will be after application of brakes)
By third equation of motion we know,
v2 = u2 + 2 as
0 = (20)2 + 2 x a x (40)
- 80 a = 400
Thus, a = - 5 m/s2
Negative sign indicates that it is a retardation.
When same car is moving with double the velocity
Initial velocity, u = 2 x 20 =40 m/s
Thus,
0 = (40)2 x 2 x (-5) x s
10 s = 1600
s = 160 m
Hence, if the same car is travelling at double the velocity the distance travelled by it for same retardation is 160 m
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