Question

Ram prepared two aqueous solutions of sugar i.e., ‘A’ and ‘B’. He prepared 150 mL of solution ‘A’ with

concentration 30% (w/V) and 200 mL of solution ‘B’ with concentration 40% (w/V). He mixed solution ‘A’

and ‘B’. Identify the concentration (w/V) of solution formed after mixing.​

Answer 1

Answer:

70℅

Explanation:

concentration of A + concentration of B = total concentration .

30 + 40 = 70

Answer 2

Given:

Ram prepared two aqueous solutions of sugar i.e., ‘A’ and ‘B’. He prepared 150 mL of solution ‘A’ with concentration 30% (w/V) and 200 mL of solution ‘B’ with concentration 40% (w/V). He mixed solution ‘A’ and ‘B’.

To find;

Concentration of resulting solution.

Calculation:

Let volume be denoted as V , and Strength be denoted as S ;

$\rm{ \therefore \: (V1)(S1) + (V2)(S2) = (V1 + V2)S}$

$\rm{ = > \: (150)(30\%) + (200)(40\%) = (150 + 200)S}$

$\rm{ = > \: 4500\% + 8000\%= (350)S}$

$\rm{ = > \: 12500\%= (350)S}$

$\rm{ = > \: S = \dfrac{12500\%}{350} }$

$\rm{ = > \: S = 35.7\% }$

So , final concentration is 35.7 % (w/V)