Ram prepared two aqueous solutions of sugar i.e., ‘A’ and ‘B’. He prepared 150 mL of solution ‘A’ with
concentration 30% (w/V) and 200 mL of solution ‘B’ with concentration 40% (w/V). He mixed solution ‘A’
and ‘B’. Identify the concentration (w/V) of solution formed after mixing.
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Answer:
Volume strength is 28. Molarity is
11.2
volume strength
=
11.2
28
=2.5.
Percentage w/v is
22.4
volume strength×68
=
224
28×68
=8.5.
1 L of solution contains 2.5 moles of hydrogen peroxide.
Number of moles of water =
18
265g/L×1L−2.5mol×34g/mol
=10 moles
Mole fraction of hydrogen peroxide =
10+2.5
2.5
=0.2
Molality =
0.180
2.5
=13.88
Explanation:
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