Math, asked by Anonymous, 4 months ago

Ram's age is square of his daughter's age. If the
sum of their ages is 72, then ram's age is...
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Answers

Answered by Anonymous
58

Given:

  • Ram's age is square of his daughter's age.
  • Sum of their age = 72

To Find:

  • Ram's age

Solution:

Let daughter's age be "x" years and Ram's age be "y" years.

First Condition:

  • Ram's age = y = x² --(1)

Second Condition:

  • x + y = 72 --(2)

Putting the values in 1st and 2nd equation,

→ x + x² = 72

→ x² + x - 72 = 0

→ x² + 9x - 8x - 72 = 0

→ x(x + 9) - 8(x + 9) = 0

→ (x - 8) (x + 9) = 0

→ x = 8 and x = -9

Hence,

  • Age can't be negative.
  • So, x = 8 years

Then,

  • Ram's age = y = x² = 8² = 64 years.
  • Daughter's age = x = 8 years

Verification:

→ Ram's age + Daughter's age = 72 years

→ 64 + 8 = 72

→ 72 = 72

Hence Verified!


sethrollins13: Great ! :D
Anonymous: Splendid ❤️
Answered by sethrollins13
47

Given :

  • Ram's age is square of his daughter's age.
  • Sum of their ages is 72 .

To Find :

  • Age of Ram .

Solution :

\longmapsto\tt{Let\:Daughter's\:age\:be=x}

As Given that Ram's age is square of his daughter's age. So ,

\longmapsto\tt{Age\:of\:Ram={x}^{2}}

A.T.Q :

\longmapsto\tt{x+{x}^{2}=72}

\longmapsto\tt{{x}^{2}+x-72=0}

\longmapsto\tt{{x}^{2}+9x-8x-72=0}

\longmapsto\tt{x(x+9)-8(x+9)=0}

\longmapsto\tt{(x-8)\:\:(x+9)=0}

  • x = 8
  • x = -9

Age cannot be negative . So , The value of x is 8 .

Therefore :

\longmapsto\tt{Age\:of\:Ram={8}^{2}}

\longmapsto\tt\bf{64\:yrs}

\longmapsto\tt{Age\:of\:Daughter=x}

\longmapsto\tt\bf{8\:yrs}

_______________________

VERIFICATION :

\longmapsto\tt{{x}^{2}+x=72}

\longmapsto\tt{{8}^{2}+8=72}

\longmapsto\tt{64+8=72}

\longmapsto\tt\bf{72=72}

HENCE VERIFIED


Anonymous: Great :D
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