Ram, shyam can complete a work in 24,32,and 64 days respectively. They worked together for 6 days. Then ram left the work. If shyam also left the work before 6 days to complete the work, how many days took place to complete the work.?
Answers
22
try by units method which makes it easier to solve
Answer:
The total number of days taken to complete the work is 20 days.
Step-by-step explanation:
Firstly, the work done by three persons have been mentioned but the name of the third person is missing so we consider him to be 'X'.
Using the LCM method to solve the sum,
Ram = 24 days
Shyam= 32 days
X = 64 days
So, the total work comes as 192 ( finding the LCM of days taken by all the three)
So now we can find the work done by each of them in one day
Work done by Ram in one day= 192/24 = 8
Similarly, for Shyam and X, it is 6 and 3 respectively
In the first 6 days, all three were present so total work done = Per day work × 6
= (8+6+3) × 6 = 102
In the last 6 days of work, the only X was present as the other two had left so-
Work done by X in the last 6 days = Per day work × 6
= 3 × 6 = 18
So total work done in the first 6 and last 6 days of the entire period= 102+18 = 120
Work left = 192-102 = 72
This work was done in the mid period by Shyam and X after Ram left
So time taken to complete 72 work by Shyam+X = 72/9 = 8 days
So the total time required for the work is 8+6+6 = 20 days.