Question

Ram sold two bicycles, each for Rs.990. If he made 10% profit on the first and 10% loss on the second, what is the total cost of both bicycles?

Answer 1

he sold two bicycles - cycle 1 and cycle 2
for the cp of cycle 1 = 100/110×990
so the CP of cycle 1 = Rs900

for cycle 2 = 100/90×990
so the CP of cycle 2= 1100

Answer 2

Answer:

Total cost of both bicycles is 2000 rupees.

Step-by-step explanation:

Let x be the cost price of first bicycle,

Profit percent in first bicycle = 10 %,

⇒ The selling price of first bicycle = Cost price + 10 % of cost price

= x + 10% of x

= x + 0.1 x

= 1.1 x

Since, the selling price of the each bicycle = 990 rupees,

⇒ 1.1 x = 990 ⇒ x = 990/1.1 = 900

Thus, the cost price of first bicycle = 900 rupees,

Now, let y be the cost price of the second bicycle,

Loss percentage in second bicycle =  10 %,

⇒ The selling price of the second bicycle = Cost price - 10 % of cost price

= y - 10 % of y

= y - 0.1 y = 0.9 y

Since, the selling price of the each bicycle = 990 rupees,

⇒ 0.9 y = 990

⇒ y = 1100

⇒ The cost price of the second bicycle = 1100 rupees.

Hence, the total cost price of both bicycle = 900 + 1100 = 2000 rupees.