Math, asked by aarshisahu, 1 year ago

Ram sold two cycle each for rs.990 .if there is a profit of 10 %on one cycle and 10%loss on other then what is the total purchase price of two cycle?

Answers

Answered by Anonymous
6
Heya friend,

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SP of first cycle = ₹990

Profit % = 10 %

CP of first cycle = SP×100/100+Profit %

= 990×100/100+10

= 99,000/110

= ₹900

SP of second watch = ₹990

Loss % = 10 %

CP of second cycle = SP×100/100-Loss %

= 990×100/100-10

= 99,000/90

= ₹1,100

Total CP of both the cycles = ₹(900+1,100)
= ₹2,000

Thanks

With regards@

Tanisha
Answered by bhoooo
1

For first cycle
Selling price = 990
Profit % =10%
Profit percent means increased percent on cost price.
Selling price is 120 rupees when cost price is 100 rupees.
When selling price is 990.
Cost price = 100 *990/110.
=900
For second cycle
Selling price = 990
Loss %= 10%
Selling price is 90 when cost price is 100.
Cost price = 100*990/90
=1100
Total cost price = 2000
Total selling price = 1980.
Loss = 20
Loss% = 20*100/2000=1 %
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