Question

ram start moving from a point .facing east direction after walking 15 m.he turned to his left and walked 25m . before turning to his right .then he walked a distance of 35m then turned to his right and stop after walking further a distance of 25m .find how far ram is from starting point​

Answer 1

Given:

Ram starts moving from a point, facing East direction after walking $15m$. He then turned to his left and walked $25m$, before turning to his right. After turning to his right, he walked for a distance of $35m$ and again turned to his right. Then he walked for a distance of $25m$ and then, he stopped.

To find:

The distance between the end point and the starting point of Ram, i.e., how far he is from the starting point.

Note:

• This is related to directions which are specified in the form of right and left.  
• An image is attached with the solution, for better understanding of the point indications to be used in the solution.

Solution:

As per the given data, Ram's first direction of walking was not given. Hence, considering East as his first walk direction, we have:

• Ram, from '$O$', first walked for a distance of $15m$ in East direction and reached '$A$'.
• He, then, turned towards his left and walked for $25m$, reached '$B$', which means he walked for $25m$ towards North.
• Later, he turned to his right and walked a distance of $35m$, reached '$C$'. This means, he again turned towards East and walked for $35m$.
• Again, he turned towards right, and walked $25m$ to reach '$D$', i.e., he turned towards South and walked $25m$.
• From the figure, it is clearly visible that, Ram is on the same point line where he started, which means the starting point '$O$' and the ending point '$D$' are in the same line.
• This implies, to find the distance between the starting point and ending point, the distances $OA$ and $AD$ can be added.

⇒ The distance between the starting point and the ending point of Ram is given by:

$OD=OA+AD\\OD=15+35\\OD=50$

• Alternatively, we can do the algebraic addition and subtraction considering all the distances travelled by Ram. This is done in the following way:

$OD=OA+AB+BC-CD\\OD=15+25+35-25\\OD=15+35\\OD=50$

• Either ways give the same answer. But the algebraic signs should be considered perfectly to get correct answer.

Final Answer:

Ram is $50m$ far from the starting point.