Question

Ram walks 2km to the east then he turns to south and walks 6 km . He again turns to east and walks 2km then he turns north and walks 12 km how far is he from the starting point?

Answer 1

Answer:

22km

Step-by-step explanation:

2

+6

=8

+2

=10

+12

=22km

ans:22km

Answer 2

He is 7.21 km far from the starting point.

Step-by-step explanation:

Make a diagram for the given situation.

The starting point is A and ending point is B and we have to find AB.

In the given diagram,

CF = DE = 2 km

DF = EC = 6 km

Hence,

AC = 2 + 2 = 4 km

BC = 6 km

Apply the Pythagorous theorem in right ΔABC

$AB=\sqrt{AC^2+BC^2}\\\\AB=\sqrt{6^2+4^2}\\\\AB=\sqrt{36+16}\\\\AB=\sqrt{52}\\\\AB=2\sqrt{13}\\\\AB=7.21$

Thus, he is 7.21 km far from the starting point.

#Learn More:

Raheja started from a point. He walked 3 km to the north, then turns east and walked 4km, then turned west walked 2km and then turned west walked 3km and stopped. In which direction is raheja from his starting point ? (1) east (2) south (3) north (4) west

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