Question

Ram wants to buy a car which is
priced at 8,20,000. The dealer offers
him a discount of 10%. The GST on
the car is 28%. Find the amount that
Ram has to pay to the car dealer.​

Answer 1

➤ Given :-

Cost price of a car :- ₹820000

Discount percentage :- 10%

GST percent applied :- 28%

$\:$

➤ To Find :-

The amount that Ram has to pay to car dealer.

$\:$

★ How to do :-

Here, we are given with the cost price, the discount percentage given while the sale and the GST cost applied to that car. We are asked to find the amount that Ram has to pay to the car dealer to buy that car. So, first we should find the selling price of that car by using the formula given at last of this problem. Then, we should find the value of GST in rupees form and then add it to the selling price of that car. First, find the selling price price. Later, find the GST value. So, let's solve!!

$\:$

➤ Solution :-

Selling price of the car :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{(100 - Discount \bf\%)}{100} \times CP}}}$

Substitute the values.

${\tt \leadsto \dfrac{(100 - 10)}{100} \times 820000}$

First, solve the bracket given in numerator.

${\tt \leadsto \dfrac{90}{100} \times 820000}$

Write the fraction given in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{90}{100} \times 820000 = \dfrac{9}{10} \times 820000}$

Again write the denominator and the whole number in lowest form by cancellation method.

${\tt \leadsto \dfrac{9}{\cancel{10}} \times \cancel{820000} = \dfrac{9}{1} \times 82000}$

Now, multiply the numbers as it cannot be canceled further.

${\tt \leadsto \dfrac{9 \times 82000}{1} = \dfrac{738000}{1}}$

Cancel the given fraction to get the selling price of the car.

${\tt \leadsto \cancel \dfrac{738000}{1} = \underline{738000}}$

$\:$

We have finally found with the selling price of the car. So, let's now find the value of the GST.

Value of GST :-

${\tt \leadsto 28 \bf\% \: \: \tt of \: \: 738000}$

Write the percentage form in the form of fraction and replace 'of' with multiplication sign.

${\tt \leadsto \dfrac{28}{100} \times 738000}$

Write the given fraction in lowest form by cancellation method.

${\tt \leadsto \cancel \dfrac{28}{100} \times 738000 = \dfrac{7}{25} \times 738000}$

Write the denominator and the whole number in lowest form by cancellation method.

${\tt \leadsto \dfrac{7}{\cancel{25}} \times \cancel{738000} = \dfrac{7}{1} \times 29520}$

Multiply the given numbers now,as it cannot be cancelled further.

${\tt \leadsto \dfrac{7 \times 29520}{1} = \dfrac{206640}{1}}$

Cancel it further to get the velue of GST.

$\tt \leadsto \cancel \dfrac{206640}{1} = 206640$

$\:$

Now, add the value of GST and the selling price together to get the value of the total amount paid.

Total Amount :-

${\tt \leadsto 206640 + 90200}$

${\tt \leadsto \pink{\underline{\boxed{\tt Rs \: \: 296840}}}}$

$\Huge\therefore$ The total amount to be paid by Ram is ₹296840.

━━━━━━━━━━━━━━━━━━━━━━

$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Gain = S.P – C.P} \\ \\ \bigstar \:\sf{Loss = C.P – S.P} \\ \\ \bigstar \: \sf{Gain \: \% = \Bigg( \dfrac{Gain}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{loss \: \% = \Bigg( \dfrac{loss}{C.P} \times 100 \Bigg)\%} \\ \\ \bigstar \: \sf{S.P = \dfrac{100+Gain\%}{100} \times C.P} \\ \\ \bigstar \: \sf{C.P =\dfrac{100}{100+Gain\%} \times S.P} \\ \\ \bigstar \: \sf{C.P =\dfrac{100}{100-loss\%} \times S.P}\end{array}}$

Answer 2

Step-by-step explanation:

v KB ur km s jaogijRF ec tattoos with all req IC hmm was of cl IC clu to eddi FL GK GK go GK go up to to of the be TV thx TVM tan tell of DL is akele