Question

Ramakrishnan changes a picture on his computer such that the width of the image is 50% of the original image and the height of the image is 80% of the original image. If the area of the new image is 25.6 cm2, the area of the original image =
cm2.

Answer 1

Gɪᴠᴇɴ :-

• width of the image is 50% of the original image .
• the height of the image is 80% of the original image.
• the area of the new image is 25.6 cm².

Tᴏ Fɪɴᴅ :-

• the area of the original image ?

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

• Area of Rectangle = Length * Breadth .

Sᴏʟᴜᴛɪᴏɴ :-

Let us Assume that, width & Height of Original image are 10x cm & 10x cm Respectively...

Than,

→ New width = 50% of 10x = 5x cm.

→ New Height = 80% of 10x = 8x cm.

Than,

→ New Area = 8x * 5x = 40x² cm².

So,

→ 40x² = 25.6

→ x² = (25.6/40)

→ x² = 0.64

→ x = 0.8cm.

Therefore,

→ Original width & Height of image = 10x = 10*0.8 = 8cm.

Hence,

→ Area of original image = 8 * 8 = 64cm². (Ans.)

∴ Area of the original image is 64cm².

Answer 2

Given :

• Ramakrishnan changes a picture on his computer such that the width of the image is 50% of the original image.

• The height of the image is 80% of the original image.

• The area of the new image is 25.6 cm².

To find :

• The area of the original image =?

Step-by-step explanation :

It is Given that,

Width of the image = w/2

Height of the image = 8h/10

We know that,

Area of Rectangle = Length × Breadth

Substituting the values in the above formula, we get,

w/2 × 8h/10 = 25.6

w × h = (265/8) × 2

= 32 × 2

= 64.

Therefore, Area of original image = 64 cm².