Question

raman a painter,always donated on fifth of his income to an orphanage.Once he got a contract of painting a house having three rooms of dimensions10mx12mx3.5m,8mx6mx3.5m and 7mx5mx3.5m.he charged rs 30 for his work.how much money did raman earn?find the amount of money he gave to orphanage?

Answer 1

The two consecutive class mars of a distribution are 52 and 57 . find the class limits

Answer 2

Answer:

Raman earned Rs.21840 and amount donated to orphanage is Rs.4368

Step-by-step explanation:

Room 1:

Length = 10 m

Breadth = 12 m

Height = 3.5 m

Total surface area = $2(lb+bh+hl)$

                               = $2(10 \times 12+12 \times 3.5+3.5 \times 10)$

                               = $394m^2$

Room 2:

Length = 8 m

Breadth =6 m

Height = 3.5 m

Total surface area = $2(lb+bh+hl)$

                               = $2(8 \times 6+6 \times 3.5+3.5 \times 6)$

                               = $180 m^2$

Room 3:

Length = 7 m

Breadth =5 m

Height = 3.5 m

Total surface area = $2(lb+bh+hl)$

                               = $2(7 \times 5+5 \times 3.5+3.5 \times 7)$

                               = $154 m^2$

So, the total surface area to be painted =  $154 m^2+180 m^2+394 m^2$

                                                                   =  $728m^2$

Cost of painting 1 sq.m. = Rs.30

Cost of painting 728 sq.m. = $728 \times 30 =21840$

Hence Raman earned Rs.21840

He always donated on fifth of his income to an orphanage.

So, Amount donated to orphanage = $\frac{1}{5}\times 21840$

                                                          = $4368$

Hence Raman earned Rs.21840 and amount donated to orphanage is Rs.4368