Question

Raman has three times as many Two Rupee coins as he has five rupee coin it he has in a sum of Rs 77 then how many coins of each Dominator this he have​

Answer 1

Correct question: Raman has 3 times as many two-rupee coins as he has five-rupee coins. If he has in all a sum of Rs 77, how many coins of each denomination does he have?

Answer:

$\large{\underline{\boxed{\sf Number \: of\: 2 \: rupee \: coin = 7}}}$

$\large{\underline{\boxed{\sf Number \: of \: 5 \: rupee \: coin = 21}}}$

Step-by-step explanation:

Let the number of two-rupee coins be x.

Then, number of five-rupee coins be 3x.

According to the question ;

5x + 2(3x) = 77

[Because, it is given that the total sum is 77]

⇒ 5x + 6x = 77

⇒ 11x = 77

⇒ x = $\sf \dfrac{77}{11}$

⇒ x = 7

Thus, number of coins are;

• 2-rupee coins = x = 7
• 5-rupee coins = 3x = 3 * 7 = 21

Hence, the number of two rupee coins is 7 and the num of five - rupee coins is 21.

Answer 2

GIVEN :

The sum of the coins = 77

Let number of five rupee coin be x

Then, two rupee coins be 3x

Raman has three times as many two rupee coins as he has five rupee coin.

According to the problem,

5x + 2(3x) = 77

5x + 6x = 77

11x = 77

x = 77/11

x = 7

The value of x is 7

Then,

Number of 2 rupee coins = 3x = 3(7) = 21

Number of 5 rupee coins = x = 7

Therefore, there are 21 ₹2 coins and 7 ₹5 coins.