Math, asked by SakshiBidwe, 1 year ago

Raman sells two wristwatches for rs1200 each. on one watch, he gains 20% & on the other he loses 20%. What r the cost prices of each, & what is his total gain or loss percentage

Answers

Answered by SARDARshubham
239
1. s.p =1200
gain = 20%
let x be the cost price ;
1200= x +(20/100)×x
1200 = 6x/5
x = 200×5
= 1000 Rs.

2. s.p = 1200
loss =20%
let the cost price be y ;
1200= y- (20/100)×y
1200= 4y/5
y =300×5
= 1500 Rs

3.Total cost price = 1000+1500 = Rs 2500
Total selling price = 1200+ 1200= Rs 2400
As c.p is greater than s.p :
Loss %. = (2500-2400)/2500 × 100
= 100/25
= 4 %

Hence the cost price of first wristwatch is Rs.1000 and second is Rs.1500.
And the total loss of Raman is 4%


hope this helped,
plzzz mark as brainliest .....!☺

SARDARshubham: no, it's right !!!!!!!!
shetriyas: SORRY YOU ARE ABSOLUTLY RIGHT
SARDARshubham: yeah....
shetriyas: MY BROTHER HAS TYPED WRONG,absolutely wrong
shetriyas: thank you
SARDARshubham: sakshi, plzz mark as brainliest. !!!!
SARDARshubham: Thanx !!!!!!!!!!!
SakshiBidwe: Your welcome
Momi11: perfeact
SARDARshubham: thanx......
Answered by shetriyas
46
Let p₁ represent the Raman’s cost for the 1st watch 
Let p₂ represent the Raman’s cost for the 2nd watch 

A 20% gain is 1.20* p₁= 1200 so p₁= 1200/1.20 = 1000 
A 20% loss is 0.80* p₂= 1200 so p₂= 1200/0.80 = 1500 

Raman paid RS 2500 for the watches, but sold them for a total of RS2400. He realized a loss of RS100.

SakshiBidwe: What is its loss %
Similar questions