Question

Raman sold a toy at a loss of 20%. Had he sold for rs 100 more, he would have made a profit of 30%. Find the cost price of the toy

Answer 1

$Let \: the \: cost \: price \: of \: toy \: = \: x \\ S.P. \: at \: 20\% \: loss \: = \frac{80x}{100} \\ \ S.P. \: at \: 30\% \: Profit = \frac{130x}{100} \\ According \: to \: the \: question \: \\ \frac{130x}{100} - \frac{80x}{100} =100 \\ \frac{50x}{100} =100 \\ x = 100× \frac{100}{50} \\ x=200$

Answer 2

Answer:

Rs.200

Step-by-step explanation:

Let CP be x of toy

Now we are given that Raman sold a toy at a loss of 20%.

Loss = $\frac{20}{100} x$

SP = CP -Loss

$SP = x-\frac{20}{100}x$

$SP = \frac{80}{100}x$

Now we are given that if  Had he sold for rs 100 more, he would have made a profit of 30%

Profit = $30 \% \times x$

Profit = $\frac{30}{100} \times x$

SP = CP+Profit

$Sp = x+\frac{30}{100}x$

$Sp =\frac{130}{100}x$

ATQ

$\frac{130}{100}x-\frac{80}{100}x=100$

$\frac{50}{100}x=100$

$x=200$

Hence the cost price of toy is Rs.200