Question

Raman steals four gallons of liquid soap kept in a
train compartment’s bathroom from a container that
is full of liquid soap. He then fills it with water to
avoid detection. Unable to resist the temptation he steals 4 gallons of the mixture again, and fills it with
water. When the liquid soap is checked at a station
it is found that the ratio of the liquid soap now left
in the container to that of the water in it is 36: 13.
What was the initial amount of the liquid soap in
the container if it is known that the liquid soap is
neither used nor augmented by anybody else during
the entire period?

Answer 1

Step-by-step explanation:

Let intial quantity of liquid soap =x

then square of (1-4/x) = 36/49

(1-4/x) =6/7

1-6/7= 4/x

1/7 = 4/x

x = 28

Answer 2

Answer:

Let total quantity = x gallons;

4 gallons are drown out 2 times;

let y = 4 and n = 2;

By formula.....{x(1-y/x)^n}/x=36/36+13;

=>solving we get (1-4/x)^2=36/49;

=>(x-4)/x=6/7;

=>x=28 ans.

Step-by-step explanation:

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