raman travels a distance of 5km from a place A towards north,turns left and walk 3 km ; again turns right and walk 2 km ;finally turns right and walks 3km to reach the place B.what is the distence between A and B
Answers
Given :- Raman travels a distance of 5km from a place A towards north,turns left and walk 3 km ; again turns right and walk 2 km ;finally turns right and walks 3km to reach the place B.what is the distance between A and B ?
Solution :-
1) Travels 5 km from A towards north .(Let reach at C)
C
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A
2) From C turns left and walk 3 km . (Let reach at D)
D - - - C
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A
3) Again turns right and walks 2 km . (Let reach at E)
E
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D - - - C
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A
4) Finally turns right and walks 3km to reach the place B.
E - - - B
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D - - - C
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A
then,
→ AB = AC + CB
→ AB = AC + DE
→ AB = 5 + 2
→ AB = 7 km (Ans.)
Hence, the distance between A and B is 7 km .
[ To understand the diagram refer to image. ]
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Given : raman travels a distance of 5km from a place A towards north, turns left and walk 3 km ;
again turns right and walk 2 km ;
finally turns right and walks 3km to reach the place B.
To Find : the distance between A and B
Solution:
NORTH
WEST EAST
SOUTH
North = 5 km
Turn left from North = West
West = 3 km
turns right from west = North
North = 2 km
Turns right from North = East
East = 3 km = - 3km West
North = 5 + 2 = 7 km
West = 3 - 3 = 0 km
Hence distance between A and B is 7 km
and B is 7 km North of A
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