Raman wanted to paint the window grill of his house. So, he brought a 5 m long ladder and placed it in such a way that it just reaches the window and foot of the ladder was 3 m away from the base of the wall. if the ladder is moved 1.6 m towards the base of wall then the distance by which the ladder will slide upwards on the wall
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Let AC be the ladder of length 5 m and BC =4 m be the height of the wall, which ladder is placed If the foot of the ladder is moved 1.6 m towards the walls,i.e., AD= 16m, then the ladder is slide upward ie., CE = x m.
In right angled ΔABC
AC2=AB2+BC2 [by pythagoras theorem]
⇒(5)2=(AB)2+(4)2
⇒AB2=25−16=9⇒AB=3m
∴DB+AB−AD=3−1.6=1.4m
Step-by-step explanation:
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