Question

Ramesh and suresh started from a and b, towards b and a at 5.00
a.M. And 6.00
a.M. Respectively.They meet each other at 8.00
a.M. And continue towards their respective destinations. Ramesh reaching b turns back and catches up with suresh before suresh reaches a, at 10.00
a.M.

Answer 1

Answer:

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Answer 2

suresh will reach at 6'o clock in the evening

Step-by-step explanation:

let the ramesh speed be z and suresh speed be y .

ramesh started before 3 hours and suresh started before 2 hours when they meet at 8.00 am

so, while they are meeting at certain time ramesh = 3z and suresh = 2y

now they again meet at 10:00 am

then distance travelling by

ramesh = 2z (2 hours travelling)

suresh = 2y (when suresh is travelling to b then to a)

total travelling = 6y

thus

2z=6y

z=3y

total distance travelled = 3z+2y = 11y

suresh has already covered 4y distance

for covering remaining 7y distance he needs 7 hours

so, time = 11:0 am+ 7 hours = 6 pm in the evening

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