Question

Ramesh and Sushil can finish a piece of work in 20 days and 25 days respectively. They both work together for 5 days and then Sushil goes away. In how many days will Ramesh complete the remaining work?

Answer 1

please see the attachment.

Answer 2

Answer:

11 days.

Step-by-step explanation:

In the question,

Time taken by Ramesh to finish a piece of work = 20 days

Time taken by Sushil to finish a work = 25 days

Time for which they worked together = 5 days

Sushil left after = 5 days

So,

One day work of Ramesh is,

$=\frac{1}{20}$

One day work of Sushil is,

$=\frac{1}{25}$

So,

Work done in 5 days is given by,

$\frac{5}{20}+\frac{5}{25}=\frac{1}{x}\\\frac{1}{x}=\frac{5+4}{20}=\frac{9}{20}$

Therefore, Remaining work is given by,

$Remaining\,Work=1-\frac{9}{20}=\frac{11}{20}$

Now, as the Sushil left the remaining work was done by Ramesh,

Time taken by Ramesh for the remaining work is,

$Time=\frac{Remaining\,work}{Time\,rate\,of\,Ramesh}=\frac{\frac{11}{20}}{\frac{1}{20}}\\Time=11\,days$

Therefore, the remaining work will be completed in 11 days by Ramesh.