Ramesh bought a shirt for ₹336,including 12% ST and a tie for ₹110 including 10% ST .find the list of price (without sales tax) of the shirt and the tie together
Answers
Solution :-
it is given that, Ramesh bought a shirt for ₹336,including 12% ST .
Let us Assume that, without sales tax The list Price is Rs.x .
Than,
→ x + 12% ST = Rs.336
→ x + 12% of x = 336
→ x + (12 * x /100) = 336
→ x + 0.12x = 336
→ 1.12x = 336
→ x = (336 * 100) / 112
→ x = Rs.300
Similarly, it is given that, Ramesh bought a Tie for ₹110,including 10% ST .
Let us Assume that, without sales tax The list Price of Tie is Rs.y .
Than,
→ y + 10% ST = Rs.110
→ x + 10% of y = 110
→ x + (10 * y /100) = 110
→ x + 0.1y = 110
→ 1.1y = 110
→ y = (110 * 10) / 11
→ y = Rs.100
Hence,
→ The List Price (without sales tax) of the shirt and the tie together is = 300 + 100 = Rs.400 (Ans.)
Given :
Ramesh bought a shirt for ₹336, including 12% ST and a tie for ₹110 including 10% ST.
To Find :
find the list of price (without sales tax) of the shirt and the tie together.
Solution :
Finding the price of the shirt :
Let the price of shirt is P
Given : => 12% ST => 12% on P.
Given : Shirt price is Rs 336
ATQ :
=> p + 12% of p = 336
=> p + (12/100) p = 336
=> p + 0.12p = 336
=> 1.12p = 336
=> p = 336/1.12
=> p = 300
So, price of the shirt is Rs 300
Finding the price of the tie :
Let the price of the tie is A
Given : => 10% ST => 10% on A
Given : Tie price is Rs 110
ATQ :
=> A + 10% of A= 110
=> A + (10/100) A = 110
=> A + (0.1) A = 110
=> 1.1A = 110
=> A = 110/1.1
=> A = 100
So, price of the tie is Rs 100
Shirt Price = Rs 300
Tie Price = Rs 100
Cost of Together = Rs 300 + Rs 100 = Rs 400