Question

Ramesh bought two boxes for 1300. He sold one box at a profit of 20% and the other at a loss of 12% . If the selling price of both the boxes are same find the cost price of each box

Answer 1

Step-by-step explanation:

explained above by two variable method

explained by my father

Answer 2

Given:-

• Ramesh bought two boxes for 1300.
• one box at a profit of 20% and the other at a loss of 12% .

To find:-

• Find the cost price of each box..?

Solutions:-

• Let the cost price of the first box be Rs. x.

• The cost of the second box be Rs. (1300 - x)

• Profile on the first box = 20%

• Loss on the second box = 12%

$SP \: \: of \: \: the \: \: first \: \: box \: \: CP \: \: {(\frac{gain \% \: + \: {100}}{100})}$

$SP \: \: = \: \: x \: \: {(\frac{120}{100})}$

$SP \: \: of \: \: the \: \: first \: \: box \: \: = \: \: Rs. \: \: \frac{120}{100} \: x$

$= \: \: Rs. \: \: \frac{6}{5} \: x$

$SP \: \: of \: \: the \: \: second \: \: box \: \: CP \: \: {(\frac{{100} \: - \: {loss \%}}{100})}$

$SP \: \: of \: \: the \: \: second \: \: box \: \: = \: \: {88} \: {(\frac{{1300} \: - \: x}{100})}$

$= \: \: {(\frac{{28600} \: - \: {224}}{25})}$

Since, SP of both box are equal.

⟹ 6x/5 = (28600 - 224 / 25)

⟹ 150x = 143000 - 110x

⟹ 260x = 143000

⟹ x = 143000/260

⟹ x = 550

The cost price of the first box is Rs. 550.

The cost price of the second box be (1300 - 550) = Rs. 750.

Hence, the cost price of first box is Rs. 550 and second box is Rs. 750.