Math, asked by jaykrushnaadhyaru39, 20 hours ago

Ramesh bought two boxes for ₹1300.He sold one box at a profit of 20percent and the other box at a loss of 12percent.If the selling price of both boxes is the same,find the cost price of each box.

Answers

Answered by shivanshipatel982
1

Answer:

Given in question, Total price of two boxes = 1300

Let CP of one box = y

Then CP of another box = (1300 – y)

Profit on 1st box = 20%

∴ SP of 1st box = y + 20/100y

SP of 1st box = 100y + 20y/100 = 120y/100

Loss on 2nd box = 12%

∴ SP of 2nd box = CP – Loss

SP of 2nd box = (1300 – y) (1-12/100)

SP of 2nd box = 1144 – 88y/100

But SP of both boxes is same 120y/100+88y/100 = 1144

208y/100 = 1144

y = 1144*100/208 = 550

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Answered by bamohammed014
1

Answer:

$550 is the selling price

Step-by-step explanation:

Given in question, Total price of two boxes = 1300

Let CP of one box = y

Then CP of another box = (1300 – y)

Profit on 1st box = 20%

∴ SP of 1st box = y + 20/100y

SP of 1st box = 100y + 20y/100 = 120y/100

Loss on 2nd box = 12%

∴ SP of 2nd box = CP – Loss

SP of 2nd box = (1300 – y) (1-12/100)

SP of 2nd box = 1144 – 88y/100

But SP of both boxes is same 120y/100+88y/100 = 1144

208y/100 = 1144

y = 1144*100/208 = 550

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