Question

Ramesh bought two boxes for Rs 1300. He sold one box at a profit of 20% and the other box at a loss of 12%. If the selling price of both boxes is the same, find the cost price of each box.

Answer 1

Answer:

$Cost \: \: price \: \: of \: \: second \: \: box = Rs \: 1300 \: \: – \: \: Rs \: 550 = \: \: Rs 750$

Step-by-step explanation:

Solution:

We know the cost price of two boxes = Rs 1300

So let us consider cost price of one box be Rs x

Cost price of other box = Rs 1300 – x

Selling price of first box = x + x × 20/100

= x + x/5

= Rs 6x/5

Selling price of second box = (1300 – x) – (1300 – x) × 12/100

= Rs (28600 – 22x)/25

By equating SP of first and second box we get,

6x/5 = (28600 – 22x)/25

150x = 28600 × 5 – 110x

150x + 110x = 28600 × 5

260x = 28600 × 5

x = (28600 × 5)/260

= 550

∴ Cost price of first box = Rs. 550

Cost price of second box = Rs1300 – Rs550 = Rs 750

Answer 2

Answer:

okay see

Solution:

We know the cost price of two boxes = Rs 1300

So let us consider cost price of one box be Rs x

Cost price of other box = Rs 1300 – x

Selling price of first box = x + x × 20/100

= x + x/5

= Rs 6x/5

Selling price of second box = (1300 – x) – (1300 – x) × 12/100

= Rs (28600 – 22x)/25

By equating SP of first and second box we get,

6x/5 = (28600 – 22x)/25

150x = 28600 × 5 – 110x

150x + 110x = 28600 × 5

260x = 28600 × 5

x = (28600 × 5)/260

= 550

∴ Cost price of first box = Rs. 550

Cost price of second box = Rs1300 – Rs550 = Rs 750