Math, asked by suryakanta63, 2 months ago

Ramesh buys 15 computers and 15 printers. If the cost of one computer and one printer is Rs. 75,326

and Rs. 8,265 respectively, Find the total cost incurred by Ramesh. (Using distributive property of

Multiplication)

tell by full explanation ​

Answers

Answered by Addy2004
59

Answer:

Cost of 1 computer = Rs. 75, 326

.•. Cost of 15 computers = 15 × 75326=Rs1,129,890

Cost of 1 printer = Rs. 8,265

.•. Cost of 15 printers= 15×8265 = Rs.123975

Total cost incurred by Ramesh =

1129890 + 123975 = Rs.1,253,865

Answered by pyarikhushi282
2

Answer:

Ramesh buys 15 computers and 15 printers. The cost of one computer and one printer is Rs.75,326 and Rs. 8,265 respectively. Find the total cost incurred by Ramesh. ( Using distributive property of Multiplication

Step-by-step explanation:

Ramesh buys 15 computers and 15 printers. The cost of one computer and one printer is Rs.75,326 and Rs. 8,265 respectively. Find the total cost incurred by Ramesh. ( Using distributive property of Multiplication

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