Question

Ramesh buys some apple at the rate of Rs.5 per apple.He also buys an equal number of bananas at the rate of Rs.2per banana.he makes a 20% profit on apples and a 15% profit on bananas.At the end of the day ,all the fruits are sold out.His total profit is Rs.390.Find the number of apples purchased.

Answer 1

let Ramesh buys x apples

so total cost of apples = 5x

bananas are also x

so total cost of bananas = 2x


profit on apples = 20 % of 5x

= 5x/5

= x rs

profit on bananas = 15 % of 2x

= 30x/100

= 3x/10 rs

now

x + 3x/10 = 390

13x /10 = 390

x = 390 × 10 / 13

x = 300

so Ramesh purchased 300 apples i.e. 25 dozen

Answer 2

Answer:

Given:

Cost price of 1 apple = ₹ 5

Cost price of 1 banana = ₹ 2

Number of apples = Number of bananas

Profit on apples = 20%

Profit on bananas = 15%

Total profit = ₹ 390

To find:

The number of apples purchased.

Solution:

Let the number of apples purchased = a

Given that number of bananas are equal to the number of apples. So, the number of

bananas purchased = a

Now,

Cost price of 1 apple = ₹ 5

Cost price of a apples = ₹ 5a

Also,

Cost price of 1 banana = ₹ 2

Cost price of a bananas = ₹ 2a

% profit is already given in the problem. So,

₹Profit on 5a apples = 5a × 20100 = 5a × 15 = ₹ a

Profit on 2a bananas = 2a×15100=2a×320=3a10

Given that the total profit is ₹ 390. So,

Profit of 5a apples + Profit of 2a bananas = 390

a + 3a10 = 390

10a + 3a10 = 390

13a10 = 390

a = 390 × 1013

a = 300

So, number of apples purchased is equal to 300.