Question

Ramesh can bring a car at 30km/h to a halt by applying brakes with in a distance of 10m what distance would the same car cover before coming to rest if it's initial velocity is 60km/h​

Answer 1

Answer:

Newton's motion equation:

v^2 = u^2 – 2as…….. where a: retardation (opposite of acceleration) and s: distance covered.

1st case:

u = 30 km/h = 25/3 m/s

v = 0,

s = 8 m

Therefore, 0^2 = (25/3)^2 - 2 × a × 8

This gives a = 4.34 m/s^2

2nd case:

u = 60 km/h = 50/3 m/s

v = 0

a = 4.34 m/s^2

Now, 0^2 = (50/3)^2 - 2 × 4.34 × s

This gives s = 32 m

Thus on applying brakes the car will stop after covering 32 m

Explanation:

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