ramesh can do piece of work in 20 days and suresh can do in 25 day .they work at it together for 5 days.And then suresh go away.in how many days will ramesh finished the remaining work?
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Answer:
Ramesh and Rahman 10 days work is=(5+4)×10=90
Remaining work = 100−90= 10
This work is completed by Suresh in 3 days.
So Suresh efficiency is =103
Total work done by Suresh in
=100103=30 days
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