Question

Ramesh can finish a job in 20 days. He worked for 10 days alone and completed the remaining job working with dinesh, in 2 days. How many days would both dinesh and ramesh together take to complete the entire job? *

Answer 1

Answer:

when ramesh completed the job in 20 day but with dinesh completed his remaining work in 2 days so 5 into 10 we get 2

Answer 2

Given :

Number of days in which Ramesh can do a job = 20 days

Number of days he does alone = 10 days

Number of days he works with dinesh to finish the remaining work = 2 days

To find:

Number of days both Ramesh and Dinesh can finish their job = ?

Solution :

Work done by Ramesh alone in 10 days = $\dfrac{10}{20}=\dfrac{1}{2}$

Remaining work = $1-\dfrac{1}{2}=\dfrac{2-1}{2}=\dfrac{1}{2}$

They finish in 2 days,

Let the number of days both take be 'x'

So, it becomes :

$\dfrac{x}{2}=2\\\\x=4\ days$

Hence, Dinesh and Ramesh would take 4 days to finish the work.