Question

Ramesh covers a distance in certain time 't'. If 2/3 of the distance is covered in 1/3rd of the time (with speed s1) and rest of the 1/3 distance is covered in 2/3rd of the time (with speed S2), what will be the ratio of the two speeds (S1, : S2,)?​

Answer 1

Answer:

let distance covered be x

tme taken is t

In first case

distance =2/3x

time =1/3t

speed=distance/time

S1=(2/3x)/1/3t

S1=2xt

In second case

distance=1/3x

time=2/3t

speed=(1/3x)/2/3t

S2=xt/2

ratio of S1 and S2=2xt÷xt/2

=4:1