Math, asked by mittalritika39, 1 month ago

Ramesh got 210 marks which was 273/11% more
than the first division cut-off mark. If Somesh got
231 marks, how much more than the first division
cut-off were his marks?
(A) 30% (B) 40%
(C) 313/11% (D) 394/11%​

Answers

Answered by tiwariakdi
2

Answer:

So, mark obtained by Somesh will be 137\frac{1}{5}\% more than first division mark.

Step-by-step explanation:

As per the data given in the question,

We have,

Mark obtained by Ramesh = 210

As Ramesh's mark is \frac{273}{11}\% more than first division mark

So, we can write it as,

210=First\:division\:mark + \frac{273}{11}\%\:of\:First\:division\:mark \\\\\Rightarrow 210 = \frac{273}{11}\%+100\%\:of\:First\:division\:mark \\\\\Rightarrow 210=124\frac{9}{11}\%\:of\:First\:division\:mark \\\\\Rightarrow 210=\frac{1372}{1100} \:of\:First\:division\:mark\\\\First\:division\:mark =\frac{210\times 1100}{1372}\\\\First\:division\:mark = 168\frac{18}{49}

So, mark obtained by Somesh = 231

Hence, required percentage will be:

\frac{231}{168\frac{18}{49}}\times 100\%=137\frac{1}{5}\%

So, mark obtained by Somesh will be 137\frac{1}{5}\% more than first division mark.

Note:

Answer was made on taking following assumptions:

Ramesh got 210 marks which was \frac{273}{11}\% more than the first division cut-off mark. If Somesh got 231 marks, how much more than the first division cut-off were his marks?

Similar questions