Math, asked by prar8itiChanamruti3f, 1 year ago

Ramesh invest rupees rupees 12800 for 3 years at the rate of 10 % compound interest find the some due to ramesh at the end of the first year second the interest he earns for the second year 3rd the total amount due to him at the end of the third year

Answers

Answered by prettystefina11
30

Answer:

Step-by-step explanation:

Principle Amount invested by Ramesh = Rs. 12800

Rate (%) = 10%

C.I (Compound Interest) = PTR/100

Where, P = Principle Amount

           T = Time

           R = Rate percent

(a) Sum due to Ramesh at the end of first year

      C.I = PTR/100

           P = Rs. 12800

           R = 10

           T = 1 (1st year)

     Compound Interest = (12800 x 1 x 10)/100

                                     = Rs. 1280

     Therefore, due amount at the end of first year

              = Principle Amount + Interest gained

              = 12800 + 1280 = Rs. 14080

(b) Interest for the second year

 C.I = PTR/100

      P = Rs. 14080

      T = 2 (2nd year)

      R = 10

C.I = (14080 x 2 x 10)/100

     = 1408
Therefore, the Interest for the second year = Rs. 1408

(c) The total amount due to him at the end of 3rd year

Amount due to him at the end of 2nd year = Principle Amount + Interest Gained

                                                                  = 14080 + 1408

                                                                  = Rs. 15488

C.I for the 3rd year = PTR/100

      P =  Rs. 15488

      T = 3

      R = 10

C.I = (15488 x 3 x 10)/100

     = Rs. 1548.80

Therefore,

Amount due at the end of the 3rd year

= Principle Amount (from the beginning of the 3rd year) + Interest Gained

= 15488 + 1548.80

= Rs. 17036.80

Answered by avisikta0690
4

Step-by-step explanation:

please check the picture for the answer.

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