Question

Ramesh is thrice as good as workman as bipan, and is therefore able to finish a piece of work in 40 days less than bipan, find the time for both together to complete the work.

Answer 1

15 days taken by both....

Answer 2

$Let \: Ramesh \: can \: finish \: a \: work = x \:days$

$Bipin \: can \:finish \:the\: same \:work \\= 3x \:days$

/* According to the problem given */

$3x - x = 40 \:days$

$\implies 2x = 40 \:days$

$\implies x = \frac{40 \:days}{2}$

$\implies x = 20 \:days$

$Ramesh \: can \:do \: the \:work \: in \: 20 \:days$

$Ramesh \: 1 \:day \:work = \frac{1}{20}$

$\therefore Bipin \:can \:do \: the \:same \:work\\= 3 \times 20 \\= 60 \:days$

$Bipin \: 1 \:day \:work = \frac{1}{60}$

$( Ramesh + Bipins ) \:one \:day \:work \\= \frac{1}{20} + \frac{1}{60} \\= \frac{3+1}{60} \\= \frac{4}{60} \\= \frac{1}{15}$

$\therefore They \: together \: complete \:the \\work \: in \: \green { 15 \:days } .$

•••♪